Use suitable identities to find the products : $(x+8)(x-10)$

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$(x+8)(x-10)$

Here,      $a=8$ and $b=(-10)$

$\therefore $ Using $(x+a)(x+b)=x^{2}+(a+b) x+a b$, 

we have :  $(x+8)(x-10) =x^{2}+[8+(-10)] x+[8 \times(-10)]=x^{2}+[-2] x+[-80] $

                     $=x^{2}-2 x-80 $

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